In reality, the problem is much simpler in the Bachelier/Normal model. A very basic analysis of Bachelier formula shows that the problem can be reduced to a single variable, as Choi et al explain in their paper. So the problem is not really one of solving, but one of approximating (the inverse of) a function.

The first step to build that function is to actually have a highly accurate slow solver as reference. This is quite easy, I just started with Choi formula and used Halley's method to refine. In reality, Halley's method is already a bit overkill on this problem: it works impressively well, 1 iteration is enough to have an insane level of accuracy, only noticeable when one works in high precision arithmetic (for example 50 digits). For double precision, Newton's method would actually be enough - I initially thought that my Halley's implementation did not work as it produced the exact same output as Newton in double precision. Li proposes the use of the SOR method, which for this exercise, behaves very much like Newton's method.

I then followed the logic from Choi et al, but working directly with in-the-money call options instead of straddles. Straddles sound neat at first (hides that we work in-the-money), but it's actually useless for the algorithm. Choi et al. ignore half of the straddle range when they use their eta transform in the paper. One other change is the mapping itself, I found a better mapping for the call options (but not that far of Choi initial idea). Finally, because I am lazy, I did not go to the pain of finding a good rational fraction approximation along with the square root problem they describe, I just tried a Chebyshev polynomial.

Unfortunately, a single Chebyshev polynomial does not work well: even with a very large (1000) degree it's not very precise, so much that I thought that my transform was garbage. I had noticed by mistake, that on another part (negative) of the interval, the Chebyshev polynomial worked actually very well to approximate something related to the volatility of another option. Suddendly came to me the idea of, like Johnson does in his Faddeeva package, using N Chebyshev polynomials on N small intervals. This is like the big heavy hammer for which everything looks like nails, but it's actually very fast to evaluate as the degree of each polynomial can then be low (7), plus a table lookup (could be coded as switch statements if one really cares about such details). The slowest part is actually the call to the log function.

The final bit is the use of a Taylor approximation for my -u/log(1-u) transform as it is not all that accurate in double precision when u is near 0. And that produces the following graph

It is interesting to note that "solving" the b.p. vol is

**10x faster**than solving the Black vol.

I wrote a small paper around all this where you'll find the details as well as Matlab code.

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